huebner@en.ecn.purdue.edu (Robert E. Huebner) (01/10/91)
In article <1991Jan9.151250.14354@cck.cov.ac.uk> csg019@cck.cov.ac.uk (-~=Zaphod=~-) writes: >In article <1991Jan3.135257.6385@maverick.ksu.ksu.edu> set@phobos.cis.ksu.edu (Steve E Tietze ) writes: > >>Is their Amiga 1500 out??? Just saw an ad for one in the Amiga Ueser International. Any one have scoop on it???? > >Yes there is, i've got one. It's not by commodore, its by a UK firm called >checkmate. All it does is turn your amiga A500 into a PC lookalike, it >put the keyboard in a new cover and puts all the electronics in a sturdy >metal case for your monitor to stand on. You can then junk your old plastic >A500 case. The good thing about this is that it allows you to fit an overider >board, which has the capability to expand and A500 beyond a B2000. > Actually, there is an "official" A1500 (to be?) released in the U.K.- by Commodore. There is bound to be a lot of confusion between this official "bundle" the the Checkmate system. The most recent info I've read on the official A1500 is that it is a re-designed case with two drives, 1 Meg, and some bundled software for #999 (thats quid). The UK market seems quite fond of these "bundled" packages. Every couple of months they're talking about a new one. This sounds like the first one to offer much beyond simple bundled software. The December issue of Amiga Format has some brief blurbs about it (more like a rumour column, the mag also had a playable demo of Lemmings from Psygnosis--neat!) Just to make things more confusing, some UK vendor is selling the A5000 upgrade kit! -- | Robert E. Huebner (Amiga Nut) | "Although generally docile, teachers | | huebner@en.ecn.purdue.edu | have been known to attack savagely | | twilight@gendep.info.com | when backed up against a wall." |
kelson@ais.org (David Lewis) (02/06/91)
> >Three things: First, argv[i] is a pointer to a char, not a char. So, you should >be looking at *argv[i]. Second, you are using the assignment operator '=' in > >#include "workbench/startup.h" > >main(int argc, char *argv[]) { > int a; > if ((a = *argv[1]) == '&') > printf("Yes it's an '&'\n"); >} > >Hope that helps. Actually.. 1) why use a int? and 2) you dont need * such as printf("%s\n",argv[1]); I would make a a character -- Internet: Kelson@ais.org
guest@ab20.larc.nasa.gov (Guest User) (04/25/91)
this is a test post from xrn -- Our father who art in heaven.. I sincerely pray that SOMEBODY at this table will PAY for my SHREDDED WHAT and ENGLISH MUFFIN.. and also leave a GENEROUS TIP...