[rec.audio.high-end] Photo-detectors in CD players

acgd@ihlpf.att.com (Andrew Charles) (06/05/91)

I have some questions which may not make sense (due to a lack of technical
background on my part). However, I'll give it a try:

What factors affect the output voltage of a photocell such as those used
in CD players? What factors affect the time it takes a photocell to reach
its "expected" output?

Is it possible that circumstances could arise in a CD player which would
affect the photocell sufficiently in these ways to either cause a misreading
of a bit (wrong voltage value reached) or cause "jitter" (photocell reaction
time is too long or too short)? If the answer to either of these is "yes",
could these circumstances arise under normal operation if the player is
not broken? If "jitter" is possible here, can it be large enough to affect
the sound?

Another way to approach this is to ask: how can a photocell fail? and if it
does (or is degrading over time) what symptoms would one expect to see at
the system level?

I've just started reading Pohlman's "Principals of Digital Audio" (2nd Ed.)
and haven't found any discussion of this. Of course, I may not have seen
it yet if it's there.

Generally, I'm wondering how much the choice of photocell matters when
a CD player is being designed.

Email or posted answers would be welcome. Technical references would also
be welcome if they aren't beyond my technical grasp (Pohlman's book is
in my range).

If I'm coming way out of left field I apologize and ask that you bear in
mind the disclaimer in the first line of this message.

Thanks,

Andrew Charles
acgd@ihlpf.att.com

basiji@milton.u.washington.edu (David Basiji) (06/06/91)

acgd@ihlpf.att.com (Andrew Charles) writes:


>I have some questions which may not make sense (due to a lack of technical
>background on my part). However, I'll give it a try:

>What factors affect the output voltage of a photocell such as those used
>in CD players? What factors affect the time it takes a photocell to reach
>its "expected" output?

Actually, your questions are very valid...

>Is it possible that circumstances could arise in a CD player which would
>affect the photocell sufficiently in these ways to either cause a misreading
>of a bit (wrong voltage value reached) or cause "jitter" (photocell reaction
>time is too long or too short)? If the answer to either of these is "yes",
>could these circumstances arise under normal operation if the player is
>not broken? If "jitter" is possible here, can it be large enough to affect
>the sound?

>Another way to approach this is to ask: how can a photocell fail? and if it
>does (or is degrading over time) what symptoms would one expect to see at
>the system level?

A photodiode detector like the ones used in CD players is basically a light
EMITTING diode operated in reverse.  Of course it is optimized for its use,
but the above is essentially true.  Like any simple diode, its current/voltage
characteristics are exponential, that is, as one shines light of the appropriate
wavelength on it and increases the intensity of that light the output voltage
rises from a negative value very quickly to a positive value with very little
current output.  As the intensity of the light increases, the output current
rises dramatically with very little change in output voltage above a nominal
0.6 volts or so.  What the CD's laser does then is to turn on and off a small
current source (the photodiode).  The current is passed through a resistor to
ground and the voltage is measured at the top (diode side) of the resistor to
convert the current to a voltage (V=IR).  That voltage is then passed into a 
device called a Schmidt trigger which outputs 0volts if the input is low (<1.5V)and outputs about 5Volts if the input is higher than 1.5volts.  Now the signal
is in a form useable by the digital circuitry downstream.  
	The photodiodes commonly have response times of less than 1uS which 
corresponds to a frequency limit of 1MHz.  Since the data is sampled at about
50KHz and there are 16bits per sample, one needs a minimum response time of
about 1.3uS.  Obviously, things seem to be cut pretty close, but it's not so
simple.  There'sa truism in engineering that the more you pay for a part the 
better the documentation.  Since I only have a sketchy tech sheet (I'm cheap),
I don't know any more than a single number to characterize the diode's response
rate.  In fact, response time is meaningless.  How is it responding?  Does it
have a maximum and minimum current?  Does the response time tell how long it 
takes to swing between them?  What I want is a slew rate.  This is the time it
takes the diode to change its output current by a fixed amount.  Ideally, I'd
get a graph of slew rate, since it may swing faster between two higher or lower
current values even though the difference is the same.  That way, I could 
operate the diode in its fastest region.  Or, given a slow diode, I could run
it very close to the threshold voltage for the Schmidt trigger so that the diode
wouldn't have to change its output very much to swing the Schmidt trigger.  
The problem is that you increase the noise level since it only takes a small
perturbation to turn a 1 to a 0 or vice versa.  All told, in my experience,
the diodes are faster than they need to be and if there was any problem,
it would probably come from the IC's downstream.  The best thing you can do is
to keep the diode clean so the output current is sufficient to swing the 
Schmidt trigger.

Sorry for the long winded response.

David Basiji

png@netcom.com (Peter Glaskowsky) (06/06/91)

> What factors affect the output voltage of a photocell such as those used
> in CD players? What factors affect the time it takes a photocell to reach
> its "expected" output?

CD players typically use photodiodes, not photocells. So-called "PIN"
photodiodes are extremely fast, sensitive, and accurate.

I'll stick a disclaimer in the middle here: my experience with photodiodes
comes from high-speed fiber optic receivers (in the GHz range), which I
worked on about a year ago, and from low-speed photometers for color video
monitor calibration (which I'm working on now, at SuperMac Technolog). I've
never worked on CD players, but I've seen several application notes on the
subject.

With that out of the way, the brief summary:

CD players bounce a laser off the disc, and a photodiode measures the
reflected beam (much detail omitted). The photodiode may be connected
so that there is no voltage across the terminals (which is common in
low-speed applications), but is typically connected in reverse-bias
mode, to maximize frequency response. The output of the photodiode is a
current, proportional to the incident light. This current is converted
to a voltage, and then a comparator produces a logic-level output which
goes on to the digital side of the circuit.

While it would be possible for the photodiode receiver circuit to have
problems with amplitude or timing accuracy, it's extremely easy to
design the circuit so that these problems don't arise.

Error rates in digital communications systems, which is basically what
we have here, are usually measured in terms of "Bit Error Rate", or BER,
expressed as a unitless ratio (error bits/total bits). At the bit rates
found in CD players (about 1.4 Mbps of data, plus overhead for format
codes, redundancy, etc.), it's almost trivial to achieve BER's of one
error per billion bits with just a couple dollars worth of parts. (That's
just for the receiver section, folks, assuming no errors in the source
material, no dust or scratches on the disc, etc. Your mileage WILL vary.)

The short-form answer is, I wouldn't expect to see a significant
contribution to the overall error rate because of problems in the
photodiode receiver circuit.

.                      png

miker@polari.UUCP (Mike Ranta) (06/07/91)

In article <12783@uwm.edu> acgd@ihlpf.att.com (Andrew Charles) writes:

>What factors affect the output voltage of a photocell such as those used
>in CD players? What factors affect the time it takes a photocell to reach
>its "expected" output?

The photodiodes used to "receive" the reflected laser beam are very fast
devices.  I know the devices used in the fiberoptics communication area
must respond at several Megahertz which is at least an order of magnitude
above CD frequencies.

>Is it possible that circumstances could arise in a CD player which would
>affect the photocell sufficiently in these ways to either cause a misreading
>of a bit (wrong voltage value reached) or cause "jitter" (photocell reaction
>time is too long or too short)? 

I doubt the photodiode could cause any problems.  Again, other factors, such
as the optics in the transport are far more likely to be marginal.  Speed
would not be the problem, but signal level from say dirty lenses might be.

>Another way to approach this is to ask: how can a photocell fail? and if it
>does (or is degrading over time) what symptoms would one expect to see at
>the system level?

As with most semiconductors, I would expect the photodiode to either work,
or not work.  The sensitivity of some optoelectronic devices can be effected
if they are overloaded.  In the case of the photodiode, this would mean
being hit with a much higher intensity of light than is probably possible.

>Generally, I'm wondering how much the choice of photocell matters when
>a CD player is being designed.

I would say it's one of the easier things to specify.  The widespread use
and technology of communication laser/fiberoptic equipment has made this
sort of thing fairly "cookbook".  The more critical aspects are the servo
design for tracking and focus, optics design, and the laser diode itself.

miker@polari.uucp (Mike Ranta)