levy@ttrdc.UUCP (Daniel R. Levy) (10/17/85)
I have a question and am open to speculation, theory, etc. concerning this. Namely, how is the pressure inside an inflated auto tire affected (if at all) by putting the car's weight on it? I seem to notice a little bit of difference between the pressure measured in a tire when it is on a loose wheel and the pressure measured in the same tire when it has been mounted on the car, but that could be measurement error. Something is supporting the quarter ton or so of force against the contact patch of the tire which is not exactly a large area either--it's obviously not all air pressure that is supporting it, yet you know that if you let out the air, the wheel will come to rest against the ground with the tire squished beneath it, so the air pressure is supporting SOMETHING, which is perhaps somehow proportional to the weight on the tire (???). So anybody who knows about this, especially who could relate the theory behind this, please either post or send me mail (I will summarize to net if warranted). Thank you. -- ------------------------------- Disclaimer: The views contained herein are | dan levy | yvel nad | my own and are not at all those of my em- | an engihacker @ | ployer or the administrator of any computer | at&t computer systems division | upon which I may hack. | skokie, illinois | -------------------------------- Path: ..!ihnp4!ttrdc!levy
levy@ttrdc.UUCP (Daniel R. Levy) (10/17/85)
I have a question and am open to speculation, theory, etc. concerning this. Namely, how is the pressure inside an inflated auto tire affected (if at all) by putting the car's weight on it? I seem to notice a little bit of difference between the pressure measured in a tire when it is on a loose wheel and the pressure measured in the same tire when it has been mounted on the car, but that could be measurement error. Something is supporting the quarter ton or so of force against the contact patch of the tire which is not exactly a large area either--it's obviously not all air pressure that is supporting it, yet you know that if you let out the air, the wheel will come to rest against the ground with the tire squished beneath it, so the air pressure is supporting SOMETHING, which is perhaps somehow proportional to the weight on the tire (???). So anybody who knows about this, especially who could relate the theory behind this, please either post or send me mail (I will summarize to net if warranted). Thank you. -- ------------------------------- Disclaimer: The views contained herein are | dan levy | yvel nad | my own and are not at all those of my em- | an engihacker @ | ployer or the administrator of any computer | at&t computer systems division | upon which I may hack. | skokie, illinois | -------------------------------- Path: ..!ihnp4!ttrdc!levy
rimey@ucbernie.BERKELEY.EDU (Ken &) (10/18/85)
>... Something is supporting >the quarter ton or so of force against the contact patch of the tire which >is not exactly a large area either--it's obviously not all air pressure that >is supporting it, yet ... Don't doubt so quick. Calculate it. Multiply the tire pressure (in pounds per square inch) by the footprint size (in square inches). You will get a quarter of the weight of your car. Ken Rimey rimey@dali.berkeley.edu ucbvax!ucbdali!rimey