bliven@Atherton.COM (Andy Bliven) (12/13/89)
There is a difference in the way bash and sh handle "$@" in a function. Here is an example in sh: $ args () { for a in "$@"; do echo $a; done } $ args 1 2 3 4 1 2 3 4 $ And the same example in bash: $ args () { for a in "$@"; do echo $a; done } $ args 1 2 3 4 1 2 3 4 $ I'm running on a Sun 3/60 with Sun UNIX 4.2 Release 3.5, and the ident string in my bash is /bin/bash: $Id: gtest.c,v 1.10 88/07/02 13:34:45 afb Exp Locker: afb $ Does anyone have a fix? Thanks, Andy Bliven ------------------------------------------------------------------- Atherton Technology mail: bliven@atherton.com 1333 Bordeaux Drive phone: 408-734-9822 Sunnyvale, California 94089 fax: 408-744-1607
chet@cwns1.CWRU.EDU (Chet Ramey) (12/14/89)
In article <15261@athertn.Atherton.COM> bliven@Atherton.COM (Andy Bliven) writes: >There is a difference in the way bash and sh handle "$@" in a >function. Here is an example in sh: There is a bug in how bash 1.04 handles "$@" in general. I have sent fixes for this to Brian, my bash does it correctly. Chet Ramey -- Chet Ramey Network Services Group "Where's my froggie?" Case Western Reserve University chet@ins.CWRU.Edu