schmidt%crimee.ics.uci.edu@PARIS.ICS.UCI.EDU ("Douglas C. Schmidt") (01/03/89)
Hi,
G++ 1.32 incorrectly handles the scope of enumerated types
declared in struct's and classes. Here's an example:
----------------------------------------
int FOO = 10;
struct foo {
enum bar { FOO, BAR };
};
main ( ) {
int i = FOO;
printf ( "i = %d\n", i); // this should print out 10
}
----------------------------------------
g++ doesn't compile the code above, complaining that:
----------------------------------------
foo.c:4: `FOO' redeclared as different kind of symbol
foo.c:1: previous declaration of `FOO'
foo.c:4: warning: `FOO' was declared `extern' and later `static'
----------------------------------------
However, according to Lippman and Moo:
``In C++, enumerations are local to the class [ or struct ] in which
they are declared.'' ( page 131, 1988 USENIX C++ Conference
Proceedings ).
Therefore, the only correct way to reference enum bar's FOO is via
the visibility operator, i.e.:
int i = foo::FOO // sets i to 0, in this case.
g++ seems to be erroneously using the C visibility rules in this case.
Doug