ngo%tammy@HARVARD.HARVARD.EDU (Tom Ngo) (01/17/90)
I think this declaration, found in the g++ info file in the node
"Function Attributes", looks like a contradiction to me. Tell me if
I'm wrong:
extern const void square ();
A function declared "const" has no effect but its return value, no?
A void function returns nothing, no?
--Tomtiemann@SUN.COM (Michael Tiemann) (01/20/90)
Date: Tue, 16 Jan 90 22:28:04 EST From: ngo%tammy@harvard.harvard.edu (Tom Ngo) I think this declaration, found in the g++ info file in the node "Function Attributes", looks like a contradiction to me. Tell me if I'm wrong: extern const void square (); A function declared "const" has no effect but its return value, no? A void function returns nothing, no? --Tom Nothing funny about this at all. The `const' in this example does not modify `void', it says that the function is `functional', and that cse can optimize away calls: int i = square (a); int j = square (b); if (i == j) // cse knows this to be true. Michael