brett@pigpen (Brett S Bourbin) (08/05/88)
I am in the process of converting my program from doing direct screen updates, to using the Blitter to do it. So far the ones I have converted are the parts that do straight moves, a minterm of $F0 meaning a direct move from SOURCE A to DEST D. Since the Blitter has three channels and one destination, can I do some math on the dest? ie. Could I make a minterm to OR sources A, B and C into the destination address D? Thanks in advance. - Brett __ __ _ __ _ | || | / || || \ Brett S Bourbin | || || || || | INTERNET: brett@PIGPEN.UMD.EDU | || || || || | \_||_/ |__||__||__| Instructional Computing Programs College Park
haitex@pnet01.cts.com (Wade Bickel) (08/05/88)
--- Yes. :^)
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INET: haitex@pnet01.CTS.COMkoster@cory.Berkeley.EDU (Herbert West) (08/09/88)
In article <2965@umd5.umd.edu> brett@pigpen.UMD.EDU (Brett S Bourbin) writes: >Since the Blitter has three channels and one destination, can I do some >math on the dest? ie. Could I make a minterm to OR sources A, B and C >into the destination address D? Certainly! It would be $FE. Look at it like this: The blitter is a table look up device. Sources A,B, and C have values of 4,2 and 1 respectively. They form a 3 bit binary number, with A as the most significant digit: ABC Now just make up 8 bits for what you want its output to be, given all possible ABC combinations(only 8) 000 We want 0 001 1 010 1 011 1 100 1 101 1 110 1 111 1 Now put the bits together sideways: 11111110 = minterm, $FE
wille@frith.msu.edu (Jeffrey Wille) (05/31/90)
I don't have the RKM's, so I hope you don't mind if I ask a simple question. When using the blitter routines, a set of minterms is required. I am familiar with boolean algebra, but I was wondering just exactly how you generate the number that corresponds to a set of minterms. Robert Wille (rbw@spock.byu.edu) You can measure a programmer's perspective by noting his attitude on the continuing viability of Fortran. -- Alan Perlis