u2zj@vax5.cit.cornell.edu (03/16/91)
I'm writing a CODE resource that is called by an application. My CODE has to open an existing resource file in the same folder as the calling application. I know the name of the resource file (eg "MyFile") but (I think) I need to append this to the full path (eg "Disk:Excel 3.0:") when I call OpenResFile(). Can someone tell me how to get the path name of the calling application's folder? Or is there some other way? Thanks, Stanton Loh u2zj@vax5.cit.cornell.edu
2fmlcalls@kuhub.cc.ukans.edu (03/16/91)
In article <1991Mar15.200429.3417@vax5.cit.cornell.edu>, u2zj@vax5.cit.cornell.edu writes: > I'm writing a CODE resource that is called by an application. > My CODE has to open an existing resource file in the same folder > as the calling application. I know the name of the resource file > (eg "MyFile") but (I think) I need to append this to the full path > (eg "Disk:Excel 3.0:") when I call OpenResFile(). > > Can someone tell me how to get the path name of the calling application's > folder? Or is there some other way? > > Thanks, > Stanton Loh > u2zj@vax5.cit.cornell.edu I'm a bit confused. Is the CODE resource, resource file, and the app ALL in the same folder? If so, just OpenResFile() will do. I'm working on a game where I do basically just that. If the resource file is in the same folder as the program calling it up, it will be found by OpenResFile(). john calhoun