nwc@cunixc.columbia.edu (Nick Christopher) (05/09/88)
In section 1.4 pg 25 of the book, is the following statement: MINIX supports separate instruction and data spaces, so a program on the IBM PC, for example, can have 64k bytes of text and another 64k bytes of data and stack segmesnts combined, for a total of 128k bytes for text, data and stack total. But in the chmem man page: The compiler sets the stack space to the largest possible value (64k - text - data) Which would indicate 64k. Also I amde a little program that all it did was malloc(1024) and it bombed at around 57k. Which is right? Is there some way of getting at that second 64k that I have missed? -- "I am the Lorvax. I speak for the machines." ______________________________________________________________________________ nwc%cunixc@columbia, columbia!cunixc!nwc BITNET: nwcus@cuvma USENET: topaz!columbia!cunixc!nwc