[net.unix-wizards] mkfs

jca (02/19/83)

	I have a question about (Gap Size) argument that is used with the
	mkfs command. You normally execute the mkfs like so:

		mkfs /dev/disk 65000 7 418

	Disk being some section of a DEC RP06 disk drive. I figured out how
	the 418 is calculated (number of tracks [heads] * number of sectors
	per track): 19 * 22 = 418. If this had been a RM05, 418 would have
	been 608 (19 * 32 = 608). Now what variables are used to calculate
	the 7. It is the same for a 200MB drive and a 300MB drive.

						Thanks for any help.
						Jack Allen
						Southern Bell
						...!sb1!jca
						(404) 529-0911