[comp.unix.questions] "make" file question

flatau@handel.CS.ColoState.Edu (flatau) (08/12/90)

I have the following "makefile" file

PAT=/ub/path/
FILES=a.f b.f
NEW=$(PAT)$(FILES)
all:
       echo $(NEW)

===========================
The output from this "make" is
 /ub/path/a.f b.f

but I would like to have
/ub/path/a.f /ub/path/b.f

Well, the question is: How to append prefix (/ub/path/) to
a list of files using "make".

flatau@handel.cs.colostate.edu

ARaman@massey.ac.nz (A.V. Raman) (08/13/90)

In article <8427@ccncsu.ColoState.EDU> flatau@handel.UUCP (flatau) writes:

>
>Well, the question is: How to append prefix (/ub/path/) to
>a list of files using "make".
>
>flatau@handel.cs.colostate.edu

One way I could think of is:

PAT=/ub/path/
FILES=a.f b.f

all:
	-for i in $(FILES); {		\
		echo $(PAT)/$$i;	\
	}

- & (Anand)

darcy@druid.uucp (D'Arcy J.M. Cain) (08/13/90)

In article <8427@ccncsu.ColoState.EDU> flatau@handel.UUCP (flatau) writes:
>I have the following "makefile" file
>
>PAT=/ub/path/
>FILES=a.f b.f
>NEW=$(PAT)$(FILES)
>all:
>       echo $(NEW)
>
>===========================
>The output from this "make" is
> /ub/path/a.f b.f
>
>but I would like to have
>/ub/path/a.f /ub/path/b.f
>
>Well, the question is: How to append prefix (/ub/path/) to
>a list of files using "make".
>
I use GNU make and I do this with the following:

NEW=$(foreach i, $(FILES), $(PAT)$i)

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