hughes@ee.rochester.edu (Tadd Hughes) (03/29/91)
Hi, I think it would be easier to use an eprom using the address lines as the 8 bit input and the output lines as the bcd output. These are extremely easy to program with a couple of components. (one shot ....) Tadd
ahill@hpdmd48.boi.hp.com (Andy Hill) (04/01/91)
Actually, this is a bit of overkill, since the 74185 is a six-bit-in, eight-bit-out part, which would imply a 64x8 PROM. I suppose fuse-programmed PROMs that small still exist. However, I guess if you're not limited by board space, the venerable 2716 EPROM (or it's bigger descendents) would do the job. I guess I'm spoiled - my first thought, when I need a simple logic function, is to reach for a 20V8 or 22V10 GAL... Andy
deanr@sco.COM (Dean Reece) (04/04/91)
To convert 8 bit binary to BCD (10 bits, I assume), try using a few 74185 chips. I'm not sure of the exact configurations, but the data sheet shows how to cascade them to get wider convertors. You'll probably need about 4 or 5 to get the width you need, but since they are only 16 pin DIPs, and they need not be 'burned', I think the are a better solution that EPROM. I think it is the National Semiconductor sheet that has all the configurations for various widths; the TI sheet I have only shows the 6 bit configuration. Also, for those who are interested, the '184 does the reverse conversion (BCD to Binary). Cheers, and happy hacking. -deanr@sco.com