[comp.sys.cbm] Kermit docs

MHM104@PSUVMXA.BITNET (07/15/89)

Would somebody out there be able to post some explanation of the commands for K
ermit? I acquired a copy of the software but don't know the use of all the comm
ands. I appreciate it!

                                Mitch

aliu@nunki.usc.edu (Alejandro Liu - "ArchLich of Navarrone") (07/16/89)

In article <89195.144622MHM104@PSUVMXA> MHM104@PSUVMXA.BITNET writes:
>Would somebody out there be able to post some explanation of the commands for K
>ermit? I acquired a copy of the software but don't know the use of all the comm
>ands. I appreciate it!
>
>                                Mitch

The two commands that would get you started is "?" and "help". You can use
the ? just like you'd use it on Unix C-kermit... For example, you type:

set ?

and gves you all the options that you cann set... so on... You can't really
put the docs in a net message, they are about 300+ Blocks! (1541 blocks)

MHM104@PSUVMXA.BITNET (08/05/89)

Several weeks ago, I posted a request for docs to Kermit. Some very nice person
 was able to send the full docs to me. Unfortunately, a problem occured with my
 files and I lost the docs before I could print them out. Could that person ple
ase send them to me once again?

                                       Mitch

MHM104@PSUVM.BITNET (08/25/89)

A few weeks ago, I requested that the kind person who origionally sent me the K
ermit docs to please resend them. I have not recieved them and whould greatly a
ppreciate someone sending them to me.

                  Mitch

scott@max.acs.washington.edu (08/25/89)

In article <89236.211914MHM104@PSUVM>, MHM104@PSUVM.BITNET writes:
> A few weeks ago, I requested that the kind person who origionally sent me the K
> ermit docs to please resend them. I have not recieved them and whould greatly a
> ppreciate someone sending them to me.
>
>                   Mitch
 
Okay, the requested documention has been sent to you.
I will be there shortly...unless I didn't make a mistake in the
e-mail address.  :)
 
Scott.