[comp.sys.amiga] Help! w/ Trumpcard & Seagate drives

jhc00614@uxa.cso.uiuc.edu (06/07/90)

     I currently have a Trumpcard 500 w/ a Seagate ST-157N-1 48 meg drive.
I just purchased a ST-296N 84 meg drive that I am chaining to the card
as well and have some formatting questions.
     Originally, with the ST-157N, the Trumpcard utilities program formatted
it with a capacity (# blocks) = 93000
      and # of cylinders      = 598 approx..
 

     Someone w/ the same setup noticed that the ST-157N specs showed the
capacity to be 94860 with 607 cylinders, and suggested I format my drive
as such and get an extra 1/2 meg or so....It worked like a charm.
(one VERY odd thing was that when I told the program the drive had 607
cylinders, it recognized only 606....when I changed it to 606, it only
recognized 605.  Therefore, I put it back to 607, and it formatted it with
606 and works like a charm to this day.)
     Anyways, to get to my question.  The ST-296N has the same problem in the
Trumpcard utilities.  The program lists the ST-296 as having:
     Capacity (# blocks) = 160,140
          # cylinders    = 785
  
     Seagate drive specs for the 296N are 165851 blocks.  Well, I'd like
to format the drive w/ the Seagate specs and get the extra space, but I
don't know how to figure out the number of cylinders to go along w/ it.
     Cross multiplying gives me an approx. figure of 813 cylinders....
Is this correct?  If somebody can offer a solution or suggestions, I'd 
really appreciate it.
                                       Thanks,
                                        Jason
                                      jhc00614@uxa.cso.uiuc.edu

bdb@becker.UUCP (Bruce Becker) (06/09/90)

In article <46200076@uxa.cso.uiuc.edu> jhc00614@uxa.cso.uiuc.edu writes:
|[...]
|     Anyways, to get to my question.  The ST-296N has the same problem in the
|Trumpcard utilities.  The program lists the ST-296 as having:
|     Capacity (# blocks) = 160,140
|          # cylinders    = 785
|  
|     Seagate drive specs for the 296N are 165851 blocks.  Well, I'd like
|to format the drive w/ the Seagate specs and get the extra space, but I
|don't know how to figure out the number of cylinders to go along w/ it.
|     Cross multiplying gives me an approx. figure of 813 cylinders....
|Is this correct?  If somebody can offer a solution or suggestions, I'd 
|really appreciate it.

	The ST296N has 820 cylinders with 6 heads.
	There are 34 sectors per track. The result
	is 167280 blocks or 83.64 MB.

-- 
  ,u,	 Bruce Becker	Toronto, Ontario
a /i/	 Internet: bdb@becker.UUCP, bruce@gpu.utcs.toronto.edu
 `\o\-e	 UUCP: ...!uunet!mnetor!becker!bdb
 _< /_	 "I still have my phil-os-o-phy" - Meredith Monk

billsey@agora.uucp (Bill Seymour) (06/11/90)

In article <46200076@uxa.cso.uiuc.edu> jhc00614@uxa.cso.uiuc.edu writes:
:
: [stuff about his hard drive]
:
:(one VERY odd thing was that when I told the program the drive had 607
:cylinders, it recognized only 606....when I changed it to 606, it only
:recognized 605.  Therefore, I put it back to 607, and it formatted it with
:606 and works like a charm to this day.)

	Remember that format starts at cylinder zero... So if it ends at
606, it has really formatted 607 cylinders. 0-606...

:     Anyways, to get to my question.  The ST-296N has the same problem in the
:Trumpcard utilities.  The program lists the ST-296 as having:
:     Capacity (# blocks) = 160,140
:          # cylinders    = 785
:  
:     Seagate drive specs for the 296N are 165851 blocks.  Well, I'd like
:to format the drive w/ the Seagate specs and get the extra space, but I
:don't know how to figure out the number of cylinders to go along w/ it.
:     Cross multiplying gives me an approx. figure of 813 cylinders....
:Is this correct?  If somebody can offer a solution or suggestions, I'd 
:really appreciate it.

	That's close enough to correct for you to use. With embedded SCSI
drives, cylinders, surfaces and blocks per track don't really mean that
much. All blocks on a embedded SCSI drive are just numbered from the start
of the drive. The smarts on the drive itself do all the rest for you. With
the Seagate drives, some of the code the drive uses internally is stored
on the first few sectors. That's why things don't exactly come out when you
divide number of heads into total blocks...

:                                       Thanks,
:                                        Jason
:                                      jhc00614@uxa.cso.uiuc.edu



     -Bill Seymour             ...tektronix!reed!percival!agora!billsey
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