TEW105@psuvm.psu.edu (09/08/90)
I am new to C programing and just received my SAS/C 5.1. Acording to the book I am using as a reference for C, the getchar() command should wait for a character input, but when I use it, the program just skips happily on by the command like it never existed. Should I be using a loop similar to what would be done with get a$ in basic? BTW, my code looked something like this: include# <stdio.h> (or whatever the standard one is> main { char showall; printf ("Show all output (y/n)? \n"); showall=getchar(); blah... blah.. blah.. } Also, anysuggestions for using SAS/C on a 2 floppy, 1 meg, no HD system? Thanks for all help! L8R, ___ | |A |IF IT FALLS ON YOUR ||_|| _ \\ | ELECTRIC DREAMS! | M |HEAD, THEN YOU KNOW ||-|| |_| |\| |_| __\\ |_____________________| I |IT'S A ROCK. DISCLAMIER: THESE ARE MY OPINIONS, NOT ANYONE| G | -BINABIK ELSE'S AND ESPECIALLY NOT THE PSU CAC'S! | A |
walker@unx.sas.com (Doug Walker) (09/13/90)
In article <90250.211833TEW105@psuvm.psu.edu> TEW105@psuvm.psu.edu writes: >include# <stdio.h> (or whatever the standard one is> > >main >{ > char showall; > > printf ("Show all output (y/n)? \n"); > showall=getchar(); > > blah... blah.. blah.. > >} Try using fgets() instead of getchar(). It gets a whole line from input, terminated by a newline character. char buffer[100]; fgets(buffer, 100, stdin); if(buffer[0] == 'y' || buffer[0] == 'Y') showall = 1; else showall = 0; blah... blah... blah... ***** =*|_o_o|\\=====Doug Walker, Software Distiller====== BBS: (919)460-7430 = *|. o.| || | o |// For all you do, this bug's for you! ====== usenet: ...mcnc!rti!sas!walker plink: dwalker bix: djwalker