lius@beach.cis.ufl.edu (Scott Liu) (04/09/88)
Recently, I wrote an Ada program with side effect on a function,
called NEXT, which is used on both type and variable declarations.
I got very weird program output when I ran it using TeleSoft Ada
compiler. Is this a compilation error or compiler-dependent feature?
Thanks for your comments.
Sying-Syang Liu
Dept. of Computer and Information Sciences
University of Florida
UUCP: {ihnp4,rutgers}!codas!ufcsv!lius
Internet mail: lius@ufl.edu
------ Program source -------------
with TEXT_IO; use TEXT_IO;
procedure SET2 is
ID:INTEGER:=0;
function NEXT return INTEGER is
begin
ID:=ID+1;
return ID;
end;
begin
declare
type BIG is record X:INTEGER:=NEXT; end record; -- ???
A:array (1..5) of BIG; -- ???
B:integer:=NEXT;
begin
for I in A'RANGE loop
PUT(INTEGER'IMAGE(A(I).X));
end loop;
PUT_LINE(INTEGER'IMAGE(B));
end;
end;
----- Program output -----
1 2 3 4 5 6
--------------------------
Note: I expected to have the output
1 1 1 1 1 2ok@quintus.UUCP (Richard A. O'Keefe) (04/09/88)
In article <14425@uflorida.cis.ufl.EDU>, lius@beach.cis.ufl.edu (Scott Liu) writes: > ID: INTEGER := 0; > function NEXT return INTEGER is > begin > ID := ID+1; > return ID; > end; > declare > type BIG is record X: INTEGER := NEXT; end record; -- ??? > A: array (1..5) of BIG; -- ??? {A is (1,2,3,4,5), not the expected (1,1,1,1,1).} This is the way ADA is generally supposed to work. For example, X, Y: INTEGER := NEXT; is defined to be equivalent to X: INTEGER := NEXT; Y: INTEGER := NEXT; In general, what matters is not how many copies of an initialiser you write, but how many things are initialised: an expression is evaluated for _each_ variable it is used to initialise. It's not the way I'd prefer it, but at least it is consistent and predictable. LRM 3.7 paras 5 and 11. LRM 3.2.1 (note para 6).