raidun@intel.com (Rashid Aidun) (12/12/90)
In smalltalk one can tell a method that its a subclass responsibility. Is there a way to do this in C++ in the same manner ? I know one can use virtual, but the method needs to still be defined right ? (example would be great). In C++ you can overload operators. Does this make sense in SmallTalk ? overload is supported, right ? Thanks... Please send replies directly to: raidun@cadev6.intel.com or post them if thats not convenient. Thank you Rashid Aidun