herrage@ntpal.UUCP (Robert Herrage) (11/13/90)
I'm sending this a different way since the first way hasn't been
working very well. So, if you're getting this again, I apologize.
Yes! You can eliminate the "not used" warnings! Below is a simple
example:
void funcname(
int x;
int y;
int z )
{
x,y; // this will eliminate the "not used" warnings
printf( "%d", z );
}reb@starwolf.Solbourne.COM (Roy Binz) (11/14/90)
> Yes! You can eliminate the "not used" warnings! Below is a simple > example: > > void funcname( > int x; > int y; > int z ) > { > x,y; // this will eliminate the "not used" warnings > > printf( "%d", z ); > > } Actually, it is even easier than that! Using your example: void funcname( int /* x */, // This may look strange, but it works int /* y */, // and it is intended to be this way! int z ) { printf( "%d", z ); } You can also completely omit the parameter names, but my experience has been that leaving them in helps other people who have to read the code. Roy Binz -- Roy Binz Solbourne Computer Inc. Domain: reb@Solbourne.COM 1900 Pike Rd. UUCP: ...!{boulder,sun}!stan!reb Longmont, Colorado 80501 Phone : 303-678-4307
tom@elan.Elan.COM (Thomas Smith) (11/15/90)
From article <1084@ntpal.UUCP>, by herrage@ntpal.UUCP (Robert Herrage): > > > I'm sending this a different way since the first way hasn't been > working very well. So, if you're getting this again, I apologize. > > Yes! You can eliminate the "not used" warnings! Below is a simple > example: > > void funcname( > int x; > int y; > int z ) > { > x,y; // this will eliminate the "not used" warnings > > printf( "%d", z ); > > } However, this could (on some compilers) generate code for the comma-separated expression "x,y;". There are two other alternatives: 1) If the variable that you don't want to use is a function parameter, as in the example above, simply leave off the parameter name from the definition. i.e. void funcname(int, int, int z) { printf("%d", z); } 2) If the variable is an automatic variable or a global (such as SCCS ids) I found that if you define an inline function that takes a parameter, but has no body, no code will be generated. i.e. inline void NotUsed(const void *anything) {} NotUsed(SCCSid); // suppresses "not used" warning Hope this helps, Thomas Smith Elan Computer Group, Inc. (415) 964-2200 tom@elan.com, ...!{ames, uunet, hplabs}!elan!tom
mat@mole-end.UUCP (Mark A Terribile) (11/15/90)
> Yes! You can eliminate the "not used" warnings! Below is a simple > example: > void funcname( > int x; > int y; > int z ) > { > x,y; // this will eliminate the "not used" warnings > > printf( "%d", z ); > > } Yes, it will eliminate the warnings, but it won't compile. I think you mean void funcname( int x, int y, int z ) { x,y; // this will eliminate the "not used" warnings printf( "%d", z ); } but it's the wrong way to do it. (It's also a bear of a way to format code.) The right way is to use the language as it is meant to be used: void funcname( int, int, int z ) { cout << z; } (Note that we also get rid of the incompletely type-checked printf() .) What if you need the `documentation' value of the x and y ? You can always place a prototype in front of the function: void funcname( int x, int y, int z ); void funcname( int, int, int z ) { . . . -- (This man's opinions are his own.) From mole-end Mark Terribile
jbate@mentor.com (John Bate) (11/17/90)
In article <878@elan.Elan.COM> tom@elan.Elan.COM (Thomas Smith) writes: >From article <1084@ntpal.UUCP>, by herrage@ntpal.UUCP (Robert Herrage): >> >> >> I'm sending this a different way since the first way hasn't been >> working very well. So, if you're getting this again, I apologize. >> >> Yes! You can eliminate the "not used" warnings! Below is a simple >> example: >> >> void funcname( >> int x; >> int y; >> int z ) >> { >> x,y; // this will eliminate the "not used" warnings >> >> printf( "%d", z ); >> >> } Here is another way: void funcname( const char *a, long i, char *b ) { (const void *) a; (void) i; (void *) b; // do something here } Hope this helps. -- John Bate, Mentor Graphics Corporation, 8500 S.W. Creekside Pl., Beaverton, OR, 97005-7191, (503) 626-7000
aw1r+@andrew.cmu.edu (Alfred Benjamin Woodard) (11/19/90)
elliott@veronica.cs.wisc.edu (James Elliott) writes: > ... I get tons of warnings about unused variables. > Normally these are very handy, but this time I >know< I am not using > them, and can't really do anything about it. This makes it difficult > for me (and Emacs) to sift actual errors out of the sea of warnings. > This might sound like a silly solution but I solved the same type of problem a while back. I was working under unix using csh and so I simply piped all my compile output through grep: EX: CC foo.c |& fgrep warning I had to use |& rather than | because I compile errors come through stderr rather than stdout. Hope this helps. -ben
richard@dataspan.dataspan.UUCP (Richard "Tiger" Melville) (11/20/90)
In article <1084@ntpal.UUCP> herrage@ntpal.UUCP (Robert Herrage) writes: > Yes! You can eliminate the "not used" warnings! Below is a simple > example: > void funcname( > int x; > int y; > int z ) > { > x,y; // this will eliminate the "not used" warnings > > printf( "%d", z ); > } I do this: void funcname(int, int, int z) { printf( "%d", z ); } -- _Q Q_ Richard Melville DataSpan Technology Inc. __ /_\) /| 237-9313 400-540 5th ave SW _\___/O____O|/O____/ \_ Calgary Alberta Canada, T2P 0M2 _/ \_