am@cl.cam.ac.uk (Alan Mycroft) (03/01/88)
In article <4030@megaron.arizona.edu> mike@arizona.edu (Mike Coffin) writes: >A simple way to understand the postincrement operator is to note that >(x++) is equivalent to ((x += 1) - 1). Not if x is a floating type. Probably also not if x is a signed integral type and has a 'sticky' overflow value (but then the program is undefined anyway).