rja@edison.GE.COM (rja) (01/18/89)
I am trying to revise some code to make it more maintainable.
As part of this, I am trying to correctly have the code use
ANSI C function prototypes. I've got a couple of questions
that I can't seem to find the answer to in references at hand.
1) How should I declare a function using prototypes when
that function has no parameters ??
example: int foo();
My compiler sees no parameters and generates a warning about
the lack of ANSI function prototypes.
2) How should I declare a function which truly returns nothing ?
My first thought was to declare "void foo();" but that still
causes my compiler to warn about a function with no return value
when it compiles the function definition.
Perhaps these are cases where the programmer should just ignore the
compiler warnings, but I'd really like to have a minimum number
( preferably zero) of warnings.
Ran
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______________________________________________________________________________gwyn@smoke.BRL.MIL (Doug Gwyn ) (01/21/89)
In article <1776@edison.GE.COM> rja@edison.GE.COM (rja) writes: >1) How should I declare a function using prototypes when > that function has no parameters ?? >example: int foo(); That means, in ANSI C, the same as in pre-ANSI C, namely, nothing is specified about the (fixed) number or types of the arguments. What you want in ANSI C is int foo(void); Actually, the form you gave is 100% compatible with this, but it does not allow the compiler to check for correct (empty) usage of the arguments to the function. >2) How should I declare a function which truly returns nothing ? void foo(/*whatever*/); > My first thought was to declare "void foo();" but that still > causes my compiler to warn about a function with no return value > when it compiles the function definition. My guess is that the function definition neglects to specify "void" return type.