maart@cs.vu.nl (Maarten Litmaath) (06/14/89)
karl@haddock.ima.isc.com (Karl Heuer) writes:
\...
\ int this[100], (*that)[100] = &this;
\which is analogous to
\ int foo(void), (*bar)(void) = &foo;
\
\This particular symmetry holds only if the explicit "&" is used. Writing
\"this" without the ampersand yields the same as "&this", but writing "foo"
\without the ampersand yields "&foo[0]", which is not the same as "&foo".
\(Though they will compare equal if brought to a common type.)
Ahum Karl, typo: this <-> foo.
--
"I HATE arbitrary limits, especially when |Maarten Litmaath @ VU Amsterdam:
they're small." (Stephen Savitzky) |maart@cs.vu.nl, mcvax!botter!maart