[net.puzzle] Two 1-liter container mixture problem.

miker@hou4b.UUCP (Mike Roberson) (09/07/84)

[ Underware - computer unmentionables ]

given:	two 1-liter containers, (will hold 1-liter + 1ml and allow stirring)
	one 1-milli-liter spoon (drip free).
	container A contains exactly 1.000-liters Alcohol (pure grain).
	container J contains exactly 1.000-liters Orange-Juice (pit free,
		and for the sake of argument, assume it to be a pure liquid)
	one cycle corresponds to:
		Taking one ml from A, putting it in J,
		and stirring until mixture is complete.
		Taking one ml from J, putting it in A,
		and stirring until mixture is complete.

Assume that if both liquids were mixed, the total would equal 2.000-liters.
(i.e.: none of this 1-liter Alcohol + 1-liter Water = 1.98 liters A&W)

show:	after one cycle:
	1) what percentage (or volume) of J is Alcohol.
	2) what percentage (or volume) of A is Juice.
	and, how many cycles will it take to:
	3) make a 4-part Juice to 1-part Alcohol mixture, (in container J);
	or for you more hard core drinkers:
	4) an equal mixture (50% Alcohol/50% Juice) in one or both containers.

Don't ask me for the answer, as my fingers are too big to push those
tiny buttons on my scientific calculator watch, and it's easier for
me to just ask a question than to try and figure it out for myself.

(Fill in),
-- 
"foop foop, deedle foople doop, bip bip."
Mike "The Guy in Suspenders" Roberson   UUCP: {ihnp4,akgua,houxm}!hou4b!miker