evan@pedsgo.UUCP (Evan Marcus) (01/14/86)
We are having an argument about how NFL scheduling is done. We know that each team plays every other team in its own division twice (home & away). And that (perhaps) the last place team in the 5 team divisions do not count, but rather make up their own 'division' for scheduling purposes. That only accounts for 6 of the 16 games. How are the other 10 determined? This actually comes from a separate question: Why didn't Miami play Cleveland during the regular season? (I know this recently came up on the net, but I wasn't paying attention, and the files have already expired on my machine.) -- NAME: Evan L. Marcus UUCP: ...vax135!petsd!pedsgd!pedsgo!evan USnail: CONCURRENT Computer Corporation (formerly Perkin-Elmer DSG) M/S 308, 106 Apple St., Tinton Falls, NJ 07724 MA BELL:(201) 758-7357 LIVE: "Hey, Evan" QUOTE: What is life? Life is one damned thing after another. - M. Twain.
nyssa@abnji.UUCP (nyssa of traken) (01/15/86)
If you are in a four team division, you play every team in your
division twice plus both fifth place teams in your conference once.
If you are in a five team division, you play every team in your division
twice.
That accounts for eight games.
If you finish first or fourth in your division, you play every
first and fourth place team in the other divisions in your conference
once.
If you finish second or third in your division, you play every
second and third place team in the other divisions in your conference
once.
That brings those teams up to twelve games.
If you finished in the top four in your division, you play the top
four teams of a single division in the other conference once. That
conference that you play rotates, so in three years, (if you finish
in the top four each year) you play four teams from each division
in the other conference.
That brings those teams up to sixteen games, the full season.
If you finished fifth, you play every team in the four team division
in your conference once, and the other fifth place team in
your conference twice.
That brings them up to fourteen games.
You then play the fifth place finishers in the other conference once.
That brings them up to sixteen games, the full season.
I hope that explains it adequately.
--
James C. Armstrong, Jnr. {ihnp4,cbosgd,akgua}!abnji!nyssa
"It's a sort of mini-clone!" Who said them, what story?bd@peora.UUCP (Bernie Dougan) (01/15/86)
>We are having an argument about how NFL scheduling is done. Every team plays every other team in its division twice (once home and once away). This is true regardless of division size (4 or 5 teams). Then the first 4 teams in every division play the first 4 teams in a division from the other conference (two home and two away). As an example, this past season the first 4 teams in the AFC East (from 1984) played the first 4 teams in the NFC Central (from 1984). In addition, the 1st and 4th place teams in each division play the 1st and 4th place teams from the other 2 divisions in their conference. (two home and two away). For example, this year Miami (1st place in AFC East in 1984) played at Denver (1st West) and at Houston (4th Central) and hosted Kansas City (4th West) and Pittsburgh (1st Central). The 2nd and 3rd place teams in a division do the same thing. For the first 4 teams in a five team division, the above rules lead to 16 games - 8 division, 4 same conference, 4 other conference. Now, the 5th place teams play the 5th place team from their conference twice. Note that Buffalo and San Diego, 1984's 5th place AFC teams, played twice in 1985. Ditto for Minnesota and Philadelphia. In addition, the 5th place teams play the 5th place teams from the other conference once each. Finally, the 5th place teams play all 4 members of the 4 team division of their conference, two at home and two away. This past season Buffalo and San Diego played all teams in the AFC Central; Minnesota and Philly played all teams in the NFC West. Therefore the 5th place teams now have 16 games - 8 division, 6 same conference, 2 other conference. Finally, the teams in a 4 team division have 16 games - 6 division, 6 same conference, 4 other conference. >This actually comes from a separate question: Why didn't Miami play >Cleveland during the regular season? In 1984, Miami finished 1st in AFC East while Cleveland finished 2nd or 3rd in AFC Central. Those teams do not play the next year. As an example for 1986, take the Miami Dolphins, first place team in the AFC East: 8 division games - home and away against Pats, Jets, Colts, Bills 4 same conference against 1st and 4th place teams in the AFC Central (Cleveland and Houston) and the AFC West (LA Raiders and San Diego ?); two of these games are home and two are on the road. 4 other conference games - top 4 teams in NFC West, two at home and two away. -- Bernie Dougan CONCURRENT COMPUTER CORPORATION (a Perkin-Elmer Company) Southern Development Center 2486 Sand Lake Road Orlando, Florida 32809 (305)850-1040