ken@turtlevax.UUCP (Ken Turkowski) (02/13/85)
The Bourne shell allows you to set the positional parameters with:
set a b c d e
so that
$1 yields a
$2 yields b
$3 yields c
$4 yields d
$5 yields e
$# yields 5
regardless of the parameters given to the shell script on the command line.
Now, my question is, how do you remove all parameters, i.e. set $# to 0?
If you just say
set
you get a listing of all of the shell variables and their values.
--
Ken Turkowski @ CADLINC, Menlo Park, CA
UUCP: {amd,decwrl,nsc,seismo,spar}!turtlevax!ken
ARPA: turtlevax!ken@DECWRL.ARPAdwight@timeb.UUCP (Dwight Ernest) (02/14/85)
> The Bourne shell allows you to set the positional parameters with: > set a b c d e > Now, my question is, how do you remove all parameters, i.e. set $# to 0? Try 'unset *'. Should work. -- --Dwight Ernest KA2CNN \ Usenet:...vax135!timeinc!dwight Time Inc. Editorial Technology Group, New York City Voice: (212) 554-5061 \ Compuserve: 70210,523 Telemail: DERNEST/TIMECOMDIV/TIMEINC \ MCI: DERNEST "The opinions expressed above are those of the writer and do not necessarily reflect the opinions of Time Incorporated." -----------------------------------------------------------------------------
garys@bunker.UUCP (Gary M. Samuelson) (02/14/85)
> The Bourne shell allows you to set the positional parameters with: > set a b c d e > $# yields 5 > regardless of the parameters given to the shell script on the command line. > > Now, my question is, how do you remove all parameters, i.e. set $# to 0? Try: set x; shift 'set x' creates a list of one parameter, x, then 'shift' deletes that one parameter. Gary Samuelson
leiby@masscomp.UUCP (Mike Leibensperger) (02/14/85)
In article <661@turtlevax.UUCP> ken@turtlevax.UUCP (Ken Turkowski) writes: >The Bourne shell allows you to set the positional parameters with: > set a b c d e >so that > $1 yields a > $2 yields b > $3 yields c > $4 yields d > $5 yields e > $# yields 5 >regardless of the parameters given to the shell script on the command line. >Now, my question is, how do you remove all parameters, i.e. set $# to 0? The following works, tho it probably isn't the fastest: : while [ $# != 0 ] do echo my $# args are: $* shift done -- Mike Leibensperger Masscomp; 1 Technology Park; Westford, MA 01886 {decvax,harpo,tektronix}!masscomp!leiby
al@mot.UUCP (Al Filipski) (02/15/85)
>Now, my question is, how do you remove all parameters, i.e. set $# to 0?
try
shift $#
--------------------------------
Alan Filipski, UNIX group, Motorola Microsystems, Tempe, AZ U.S.A
{seismo | ihnp4 } ! ut-sally ! oakhill ! mot ! al
--------------------------------
Your ad could appear in this space.ado@elsie.UUCP (Arthur David Olson) (02/16/85)
> > Now, my question is, how do you remove all parameters, i.e. set $# to 0? > > try > shift $# Alas, this fails (at least on our 4.1bsd system) if $# was zero to begin with. Instead try set x ; shift or, to ensure that flags are preserved, try set -$- x ; shift -- Shell Oil surely has some legal claim on "Shell." -- UUCP: ..decvax!seismo!elsie!ado ARPA: elsie!ado@seismo.ARPA DEC, VAX and Elsie are Digital Equipment and Borden trademarks
ado@elsie.UUCP (Arthur David Olson) (02/16/85)
> > Now, my question is, how do you remove all parameters, i.e. set $# to 0? > > try > shift $# Alas, this fails (at least on our 4.1bsd system) if $# was zero to begin with. Instead try set x ; shift -- Shell Oil surely has some legal claim on "Shell." -- UUCP: ..decvax!seismo!elsie!ado ARPA: elsie!ado@seismo.ARPA DEC, VAX and Elsie are Digital Equipment and Borden trademarks
guy@rlgvax.UUCP (Guy Harris) (02/16/85)
> > The Bourne shell allows you to set the positional parameters with: > > set a b c d e > > Now, my question is, how do you remove all parameters, i.e. set $# to 0? > > Try 'unset *'. Should work. I did try it with the System III shell; it said: unset: not found "unset" must have been added in System V Release 1.0 or 2.0. Guy Harris {seismo,ihnp4,allegra}!rlgvax!guy
tim@cithep.UucP (Tim Smith ) (02/18/85)
set foo
shift
--
Duty Now for the Future
Tim Smith
ihnp4!{wlbr!callan,cithep}!timgwyn@brl-tgr.ARPA (Doug Gwyn <gwyn>) (02/20/85)
> Try 'unset *'. Should work.
Not only is "unset" only found in the latest Bourne shell,
but the suggestion does not work anyway. The wildcard "*"
expands to a list of filenames; unless that happens to
include all the set arguments (which it might, depending
on the application) that is not what is desired.mcferrin@inuxc.UUCP (P McFerrin) (02/20/85)
To set $# to zero: set "" ; shift
carl@pyuxww.UUCP (C Hoffman) (02/21/85)
Try shift $#
al@mot.UUCP (Al Filipski) (02/22/85)
>> > The Bourne shell allows you to set the positional parameters with: >> > set a b c d e >> > Now, my question is, how do you remove all parameters, i.e. set $# to 0? >> >> Try 'unset *'. Should work. > >I did try it with the System III shell; it said: > > unset: not found > >"unset" must have been added in System V Release 1.0 or 2.0. > > unset was added in V.2. You can remove named shell variables with it. There may be a way to remove positional parameters with it, but 'unset *' doesn't work on our system (doesn't the shell expand the * into filenames?). someone pointed out that the other solution posted (shift $#) doesn't work under 4.1 when $# is already 0. It works fine under V.2. -------------------------------- Alan Filipski, UNIX group, Motorola Microsystems, Tempe, AZ U.S.A {seismo | ihnp4 } ! ut-sally ! oakhill ! mot ! al -------------------------------- May the peace of Landru be with you.