dfh@scirtp.UUCP (David F. Hinnant) (08/25/85)
Enclosed below is a C translation of the famous "Whetstone Benchmark"
from the original Algol version. I have inserted printf()'s as a
compiler option. I think this translation is accurate. The only
numbers I have to compare with are from an old Ridge-32 machine, and
these are from a Pascal translation (I caught one error in their
translation). If anyone has any nunbers from FORTRAN, Pascal, or Algol
versions of the Whetstone, I would very much like to see them.
David Hinnant
SCI Systems, Inc.
{decvax, akgua}!mcnc!rti-sel!scirtp!dfh
P.s., there is a .signature file at the end of the listing.
===========================================================================
/*
* Whetstone benchmark in C. This program is a translation of the
* original Algol version in "A Synthetic Benchmark" by H.J. Curnow
* and B.A. Wichman in Computer Journal, Vol 19 #1, February 1976.
*
* Used to test compiler optimization and floating point performance.
*
* Compile by: cc -O -s -o whet whet.c
* or: cc -O -DPOUT -s -o whet whet.c
* if output is desired.
*/
#define ITERATIONS 10 /* 1 Million Whetstone instructions */
#include "math.h"
double x1, x2, x3, x4, x, y, z, t, t1, t2;
double e1[4];
int i, j, k, l, n1, n2, n3, n4, n6, n7, n8, n9, n10, n11;
main()
{
/* initialize constants */
t = 0.499975;
t1 = 0.50025;
t2 = 2.0;
/* set values of module weights */
n1 = 0 * ITERATIONS;
n2 = 12 * ITERATIONS;
n3 = 14 * ITERATIONS;
n4 = 345 * ITERATIONS;
n6 = 210 * ITERATIONS;
n7 = 32 * ITERATIONS;
n8 = 899 * ITERATIONS;
n9 = 616 * ITERATIONS;
n10 = 0 * ITERATIONS;
n11 = 93 * ITERATIONS;
/* MODULE 1: simple identifiers */
x1 = 1.0;
x2 = x3 = x4 = -1.0;
for(i = 1; i <= n1; i += 1) {
x1 = ( x1 + x2 + x3 - x4 ) * t;
x2 = ( x1 + x2 - x3 - x4 ) * t;
x3 = ( x1 - x2 + x3 + x4 ) * t;
x4 = (-x1 + x2 + x3 + x4 ) * t;
}
#ifdef POUT
pout(n1, n1, n1, x1, x2, x3, x4);
#endif
/* MODULE 2: array elements */
e1[0] = 1.0;
e1[1] = e1[2] = e1[3] = -1.0;
for (i = 1; i <= n2; i +=1) {
e1[0] = ( e1[0] + e1[1] + e1[2] - e1[3] ) * t;
e1[1] = ( e1[0] + e1[1] - e1[2] + e1[3] ) * t;
e1[2] = ( e1[0] - e1[1] + e1[2] + e1[3] ) * t;
e1[3] = (-e1[0] + e1[1] + e1[2] + e1[3] ) * t;
}
#ifdef POUT
pout(n2, n3, n2, e1[0], e1[1], e1[2], e1[3]);
#endif
/* MODULE 3: array as parameter */
for (i = 1; i <= n3; i += 1)
pa(e1);
#ifdef POUT
pout(n3, n2, n2, e1[0], e1[1], e1[2], e1[3]);
#endif
/* MODULE 4: conditional jumps */
j = 1;
for (i = 1; i <= n4; i += 1) {
if (j == 1)
j = 2;
else
j = 3;
if (j > 2)
j = 0;
else
j = 1;
if (j < 1 )
j = 1;
else
j = 0;
}
#ifdef POUT
pout(n4, j, j, x1, x2, x3, x4);
#endif
/* MODULE 5: omitted */
/* MODULE 6: integer arithmetic */
j = 1;
k = 2;
l = 3;
for (i = 1; i <= n6; i += 1) {
j = j * (k - j) * (l -k);
k = l * k - (l - j) * k;
l = (l - k) * (k + j);
e1[l - 2] = j + k + l; /* C arrays are zero based */
e1[k - 2] = j * k * l;
}
#ifdef POUT
pout(n6, j, k, e1[0], e1[1], e1[2], e1[3]);
#endif
/* MODULE 7: trig. functions */
x = y = 0.5;
for(i = 1; i <= n7; i +=1) {
x = t * atan(t2*sin(x)*cos(x)/(cos(x+y)+cos(x-y)-1.0));
y = t * atan(t2*sin(y)*cos(y)/(cos(x+y)+cos(x-y)-1.0));
}
#ifdef POUT
pout(n7, j, k, x, x, y, y);
#endif
/* MODULE 8: procedure calls */
x = y = z = 1.0;
for (i = 1; i <= n8; i +=1)
p3(x, y, &z);
#ifdef POUT
pout(n8, j, k, x, y, z, z);
#endif
/* MODULE9: array references */
j = 1;
k = 2;
l = 3;
e1[0] = 1.0;
e1[1] = 2.0;
e1[2] = 3.0;
for(i = 1; i <= n9; i += 1)
p0();
#ifdef POUT
pout(n9, j, k, e1[0], e1[1], e1[2], e1[3]);
#endif
/* MODULE10: integer arithmetic */
j = 2;
k = 3;
for(i = 1; i <= n10; i +=1) {
j = j + k;
k = j + k;
j = k - j;
k = k - j - j;
}
#ifdef POUT
pout(n10, j, k, x1, x2, x3, x4);
#endif
/* MODULE11: standard functions */
x = 0.75;
for(i = 1; i <= n11; i +=1)
x = sqrt( exp( log(x) / t1));
#ifdef POUT
pout(n11, j, k, x, x, x, x);
#endif
}
pa(e)
double e[4];
{
register int j;
j = 0;
lab:
e[0] = ( e[0] + e[1] + e[2] - e[3] ) * t;
e[1] = ( e[0] + e[1] - e[2] + e[3] ) * t;
e[2] = ( e[0] - e[1] + e[2] + e[3] ) * t;
e[3] = ( -e[0] + e[1] + e[2] + e[3] ) / t2;
j += 1;
if (j < 6)
goto lab;
}
p3(x, y, z)
double x, y, *z;
{
x = t * (x + y);
y = t * (x + y);
*z = (x + y) /t2;
}
p0()
{
e1[j] = e1[k];
e1[k] = e1[l];
e1[l] = e1[j];
}
#ifdef POUT
pout(n, j, k, x1, x2, x3, x4)
int n, j, k;
double x1, x2, x3, x4;
{
printf("%6d%6d%6d %5e %5e %5e %5e\n",
n, j, k, x1, x2, x3, x4);
}
#endif
=======================================================================
--
David Hinnant
SCI Systems, Inc.
{decvax, akgua}!mcnc!rti-sel!scirtp!dfh