CSvax:Pucc-H:Pucc-I:ags@pur-ee.UUCP (09/12/83)
Here is a different "proof" that 0=1 for you calculus fans. Take the basic integration-by-parts formula: {integral} u dv = uv - {integral} v du and let u = 1 / log x, v = log x. Then du = - (1/x) * (1/log x)**2 dx and dv = dx / x. Substituting: {integral} dx / (x log x) = 1 + {integral} dx / (x log x) Cancelling like terms: 0 = 1. Dave Seaman pur-ee!pucc-I!ags
ecn-ec:ecn-pc:ecn-ed:vu@pur-ee.UUCP (09/13/83)
Unimaginable. How about: {integral} dx = 1 + {integral} dx ???????? DON'T YOU KNOW that there is a constant of integration ?????????? Hao-Nhien Vu (pur-ee!vu)