[net.math] 0=1

CSvax:Pucc-H:Pucc-I:ags@pur-ee.UUCP (09/12/83)

Here is a different "proof" that 0=1 for you calculus fans.  Take the
basic integration-by-parts formula:

	{integral} u dv = uv - {integral} v du

and let u = 1 / log x, v = log x.

Then du = - (1/x) * (1/log x)**2 dx
and  dv = dx / x.  

Substituting:

	{integral} dx / (x log x) = 1 + {integral} dx / (x log x)

Cancelling like terms:

	0 = 1.

			Dave Seaman
			pur-ee!pucc-I!ags

ecn-ec:ecn-pc:ecn-ed:vu@pur-ee.UUCP (09/13/83)

	Unimaginable. How about:

{integral} dx = 1 + {integral} dx      ????????

	DON'T YOU KNOW that there is a constant of integration ??????????

	Hao-Nhien Vu (pur-ee!vu)