[net.math] Dumb Question

giles@ucf-cs.UUCP (Bruce Giles) (02/25/84)

.< kernel for the line eater

This is a really dumb question, but I can't figure out where else to
turn....

For complex numbers a, b, and c; is (a ^ b ^ c) equal to:

(1):  a ^ (b ^ c)

(2):  (a ^ b) ^ c,  or

(3):  a ^ (b * c)



ave discordia				going bump in the night ...
bruce giles

decvax!ucf-cs!giles			university of central florida
giles.ucf-cs@Rand-Relay			orlando, florida 32816

leimkuhl@uiuccsb.UUCP (02/28/84)

#R:ucf-cs:-119800:uiuccsb:9700025:000:214
uiuccsb!leimkuhl    Feb 27 13:42:00 1984



	The operator ^ is non-associative, so a^b^c has no meaning--
 	you must specify the order in which the operations are to be
	performed.

	Perhaps this answers your questions: a^(b^c) != (a^b)^c.

Ben Leimkuhler

ljdickey@watmath.UUCP (Lee Dickey) (03/31/84)

   > For complex numbers a, b, and c; is (a ^ b ^ c) equal to:
   >   (1):  a ^ (b ^ c)
   >   (2):  (a ^ b) ^ c,  or
   >   (3):  a ^ (b * c)
 
Your question is not dumb, it is a perfectly natural one.
To give an explanation, I would like to talk about "+", another dyadic
function.  It is a well known property of integers, rationals, reals, 
complexes (and other things, for that matter) that

         (a+b)+c  =  a+(b+c)

That is why the expression "a+b+c" makes any sense at
all, because addition is *defined* for only two numbers at a time, not
for three or more.  Now, what about exponentiation?  It, like addition,
is defined for only two numbers at a time.  

Now, does the expression "a^b^c" make sense?
Most professional mathematicians are a bit twitchie about it,
simply because of the observation that you made that gave rise
to the question, namely that expressions (1) and (2) are not equivalent.
I guess I am saying that there is no consensus, and that the
pros try to be un-ambiguous about it by putting in the parentheses.


-- 
  Lee Dickey, University of Waterloo.  (ljdickey@watmath.UUCP)
                      ...!allegra!watmath!ljdickey
                ...!ucbvax!decvax!watmath!ljdickey

gwyn@brl-vgr.ARPA (Doug Gwyn ) (04/03/84)

The tradition is to make exponentiation right-associative so that
	a ^ b ^ c
is the same as
	a ^ ( b ^ c ).
A little thought should make clear why left-associativity would not
be as useful a convention.