bennison@turtle.DEC (06/04/84)
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One solution to the problem that I get by fooling around with
matrices for a few minutes is this:
assume we have n players, with n even.
let d(i,j) be the day that the ith and jth players play.
then   d(i,j) = (i + j - 1) mod n-1  for i < j < n
and    d(i,n) = (2i - 1) mod n-1  for i < n
    				Vick Bennison
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