**pizer@ecsvax.UUCP** (07/12/84)

Just to keep you on your toes, I have ANOTHER problem, this one I have yet to solve, although I've just about got it (decided to put it up before din-din). This figure is more difficult to draw, so read through the description before trying to draw it. First start with right triangle ABC, where A is rt. and where AC is the longer leg. Then draw point D on side AC, such that DB=DC. Finally, draw point F on BC such that AF is perpindicular, and such that CF=CD. Given: BD=DC=FC=1 and that AB is prpndclr to AC and that AF is prpndclr to BC, FIND: AC. Good luck, leave answer in radical form. Billy Pizer (pizer@ecsvax) {look out M.C.!}