ran@ho95b.UUCP (RANeinast) (02/07/85)
# >Sorry, folks, but I made a mistake. The equation I meant is as follows: > > ,, , > y (t) = K/(y^2) y (0)=K1, y(0)=K2. > >Mike Moroney This one's almost as easy as the mistake. Multiply both sides by y' y'*y''=K*(y^(-2))*y' Both sides are now perfect differentials. Integrate once and get y' in terms of y. Now look it up in an integral table. -- ". . . and shun the frumious Bandersnatch." Robert Neinast (ihnp4!ho95c!ran) AT&T-Bell Labs