andrews@yale.ARPA (Thomas O. Andrews) (02/20/85)
*** What's this line doing here? *** Recently, the following problem was posted in net.math: [Paraphrased - I can't find the original article.] Find sequence a1,a2,a3,... such that oo ---- \ a n f(x)= \ n x / ----- satisfies f(n)=a . / n! n ---- n=0 I believe I've found a nice, 'simple' function f that does the trick. Let c be a complex root of c=exp(c). (Such roots exist.) Let n a = c . n Then f(x)= {summation above} = exp(cx) . Hence f(n)=exp(cn). n But exp(c)=c, so exp(cn)= c = a n. We can bet a solution of this problem with the a 's real by taking n __ ____ b = a + a (Where x+yi =x-yi.) n n n Then we get _ f(x)=exp(cx)+exp(cx). In particular, if c=u+vi, then we can write f(x)=exp(ux) (exp(vxi)+exp(-vxi)) = 2*exp(ux)*cos(vx). -- Thomas Andrews Have you killed a yellow pig today?