andrews@yale.ARPA (Thomas O. Andrews) (02/20/85)
*** What's this line doing here? ***
Recently, the following problem was posted in net.math:
[Paraphrased - I can't find the original article.]
Find sequence a1,a2,a3,... such that
oo
----
\ a n
f(x)= \ n x
/ ----- satisfies f(n)=a .
/ n! n
----
n=0
I believe I've found a nice, 'simple' function f that does the trick.
Let c be a complex root of c=exp(c). (Such roots exist.)
Let n
a = c .
n
Then f(x)= {summation above} = exp(cx) . Hence f(n)=exp(cn).
n
But exp(c)=c, so exp(cn)= c = a
n.
We can bet a solution of this problem with the a 's real by taking
n
__ ____
b = a + a (Where x+yi =x-yi.)
n n n
Then we get
_
f(x)=exp(cx)+exp(cx). In particular, if c=u+vi, then we can write
f(x)=exp(ux) (exp(vxi)+exp(-vxi)) = 2*exp(ux)*cos(vx).
--
Thomas Andrews
Have you killed a yellow pig today?